Question

What is the area of the isosceles trapezoid shown?

Answer 1

Area of a trapezoid is the average of the bases times the height. (9+4.5)/2 = 13.5/2 = 6.75. 6.75 is the average of the bases you have to multiply that number by the height so 6.75x6= 40.5cm squared. The correct answer is C.

Answer 2

Answer: C.
`40.5\ cm^2`

Explanation:

The area of a trapezoid is given by :-

`A=(1)/(2)h(a+b)`, where a and b are the lengths of the opposite parallel sides and h is height.

From the given figure , we have an isosceles trapezoid with

a= 4.5 cm ; b= 9 cm and h = 6 cm.

Then, the area of the isosceles trapezoid will be :-

`A=(1)/(2)(6)(4.5+9)\\\\=(3)(13.5)=40.5\ cm^2`

Hence, the area of the isosceles trapezoid =
`40.5\ cm^2`