Question

How many grams of ozone, O3, contains 2.791x1023 oxygen atoms?

Answer 1

22.25g

Step-by-step explanation:

1 mole of O3 = 3(16g) = 48g

1 mole of O3 has 6.02 x 10^23 atoms

=> 48 g of O3 has 6.02 x 10^23 atoms

so the mass of O3 with 2.791 x 10^23 is

(48)(2.791 x 10^23)/(6.02 x 10^23) = 22.25g