Question

Use the given conditions to write an equation for the line in​ point-slope form and​ slope-intercept form.

Answer 1

I will do the work only for Slope-Intercept form, as to preserve time. (I will still provide the answer, just not the work for point slope)

Slope =
`(y2-y1)/(x2-x1)`

Substitute
y2 = 13
y1 = -3
x2 = 3
x1 = -3
Slope =
`(13 - (-3))/(3-(-3))`

Simplify
Slope =
`(13+3)/(3+3)`

Solve
Slope =
`(16)/(6)`
Slope = 16/6

Simplify
Slope = 8/3
y = 8/3x + B

Now we find B (substitute 3,13 for x and y)
13 = (8/3)(3) + B

Solve for B
B = 5
y = 8/3x + 5 is the slope-intercept answer
and
8x − 3y + 15 = 0 is the point slope answer