The probability that she gets a ride 3 days in the week is 0.309. The probability that she gets a ride to work at least 2 times in the week is 0.969.
This is binomial, as there are two outcomes, the probability of one happening does not affect the other, and there is a fixed number of trials.
For three rides to work that week,

To find the probability that she gets a ride at least twice that week, we first find the probability that she does not get a ride at all that week or she only gets a ride one day; then we subtract that from 1:
![1-[P(X=0)\text{ or }P(X=1)] \\ \\=1-(_5C_0(0.7)^0(1-0.7)^(5-0)+_5C_1(0.7)^1(1-0.7)^(5-1)) \\ \\=1-((5!)/(0!5!)(0.7)^0(0.3)^5+(5!)/(1!4!)(0.7)^1(0.3)^4) \\ \\=1-(0.00243+0.02835)=1-0.03078=0.96922\approx0.969](https://img.qammunity.org/2019/formulas/mathematics/high-school/437npw18beud5ylaua3u5j7qtocup4oeen.png)