Question

How much heat energy is absorbed by 10g of silver if it increases in temperature from 10°c to 300°c ? The specific heat of silver is 0.235 j/g °c?

Answer 1

Q = m*Cs*deltaT = 681J

Answer 2

Given mass of silver = 10 g

Initial temperature =
`10^(0)C`

Final temperature =
`300^(0)C`

Temperature change ΔT =
`T_(final)-T_(initial) = 300^(0)C-10^(0)C`

=
`290^(0)C`

Specific heat of silver, C =
`0.235 (J)/(^(0)C.g)`

The relation between heat, mass, specific heat and temperature change is,

`Heat(q) = m C(`ΔT)

Heat =
`10. g(0.235(J)/(^(0)C)(290^(0)C)`

= 681.5 J