Question

J has a coordinates of (10,-2) and N has coordinates of (-4,6) find the midpoint of JN.

Answer 1

The midpoint of a segment refers to the point in the middle of any segment. This can be find by using the formula, M=(x1+x2/2,y1​+y2/2​​).

In this exercise is given that the segment JN, contains the points J and N, with coordinates (10,-2) and (-4,6) receptively. It is asked to find the midpoint of the segment, to do that you should substitute the given coordinates into the Midpoint Formula.

M=(x1+x2/2,y1​+y2/2​​)
M=(10-4/2,-2+6/2)
M=(6/2,4/2)
M=(3,2)

The midpoint of the segment JN, is the coordinate (3,2).

Answer 2

Add the x-coordinates and divide by 2.
Add the y-coordinates and divide by 2.


`((10 + (-4))/(2), (-2 + 6)/(2))`


`((6)/(2), (4)/(2))`


`(3, 2)`