Answer: B details to simplify A'B(D' + C'D) + B(A + A'CD) start with ( D' +C'D) = (D' + C') likewise (A + A'CD) = (A + CD) This gives A'B(D' + C') + B(A + CD)= ...
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[math]A'B (D'+C'D) + B (A+ A'CD)[/math] [math]= A'B (D'+D)(D'+C') + B (A+ A')(
Step-by-step explanation: