Answer:
$10 bill = 14 and $20 bill = 16.
Explanation:
Given : A cashier has 30 bills, all of which are $10 or $20 bills. The total value of the money is $460.
To find : How many of each type of bill does the cashier have.
Solution : We have given that
A cashier has 30 bills
Let bill of $10 = x .
Bill of $20 = y .
Money of $10 = 10x .
Money of $20 = 20y.
Total bill
x + y = 30-------(1)
10x + 20y = 460-----(2)
On multiplying equation 1 by 10 and subtracting from equation 2.
10x + 20 y = 460
(-)10x +(-) 10 y = (-)300
______________
0 + 10 y = 160 .
On dividing by 10
y = 16 .
Plug y = 16 in equation 1
x + 16 = 30
On subtracting both sides by 16.
x = 30 - 16.
x = 14
Therefore, $10 bill = 14 and $20 bill = 16.