The given question is a binomial distribution
Probability for binomial distribution = P = nCr * (p)^r * (q)^(n-r)
where p = probability of success(.25)
q = probability of failure(.75)
n = total outcomes
r = required number of outcomes
1- P(from 3 to 6 have blowouts) = P(3<=X<=6)= P(X= 3)+P(X= 4)+P(X= 5)P(X= 6)
2- P(fewer than 4 have blowouts) = P(X=0) + P(X=1) + P(X=2) + P(X=3)
3- P(more than 5 have blowouts)= 1- P(X<= 5) = 1-[ P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5) ]