Question

One mole of nitrogen and one mole of neon are combined in a closed container at stp. part a how big is the container?

Answer 1

1 mole of any gas under STP has volume 22.4 L,
we have 2 mole of gas, so volume of container should be 2*22.4 L= 44.8 L

Answer 2

V=44.8L

Step-by-step explanation:

Hello,

This problem can be solved by using the ideal gas equation:

`PV=nRT`

Nonetheless, we've got two different gases, nitrogen and neon, whose total moles turn out into 2 mol and the STP conditions which are 1 atm and 0 ºC, thus, the volume that accounts for the container's size is computed via:

`V=(2mol*0.082 (atm*L)/(mol*K) * 273.15K)/(1atm) \\V=44.8L`

Best regards.