Question

How many times larger is (1.008 x 101) than (6 x 10-f)?

0.168
5.95
11.682
16.8

Answer 1

11.682 many times larger

Answer 2

16.8

Explanation:

To find how many times larger (1.008 × 10¹) is than (6 × 10⁻¹), divide the first expression by the second expression:

`\implies (1.008 * 10^1)/(6 * 10^(-1))`

`\textsf{Apply the fraction rule} \quad (ab)/(cd)=(a)/(c) * (b)/(d):`

`\implies (1.008)/(6) * (10^1)/(10^(-1))`

Divide the numbers 1.008 and 6:

`\implies 0.168 * (10^1)/(10^(-1))`

`\textsf{Apply the exponent rule} \quad (a^b)/(a^c)=a^(b-c):`

`\implies 0.168 * 10^((1-(-1))`

Simplify:

`\implies 0.168 * 10^(2)`

`\implies 0.168 * 10 * 10`

`\implies 1.68 * 10`

`\implies 16.8`