Given:
Power of first motor (P₁) = 1500 Watts = 1500 W× (1 hp / 746 W) = 2.0 hp
Power of second motor (P₂)= 2200 Watts = 2200 W× (1 hp / 746 W) ≈ 3.0 hp
Mass of Box (m) = 100 kg
Lifted height (h) = 20 m
Formula Used: Work done = Power × time
or, W = P × t
In this case, work done by both the motors will be same because work done will be equal to the change in potential energy which is path dependent. Since, in both these cases height is same. So, only first motor will take more time as it has less power than second motor.
W₁ = P₁×t₁ and W₂ = P₂×t₂
∵ W₁ = W₂
or, P₁×t₁ = P₂×t₂
or, t α (1/P)
That is, time is inversely proportional to the power
Hence, the second motor will do work fast as compare to the first motor.