Question

The volume of an automobile air bag was 66.8 l when inflated at 25 °c with 77.8 g of nitrogen gas. what was the pressure in the bag in kpa

Answer 1

For this question we can use the ideal gas equation,
PV = nRT
P - pressure
V - volume - 66.8 / 1000 m³
n - number of moles - 77.8 g/ 28 g/mol = 2.77 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - 25 °C + 273 = 298 K
substituting these values in the equation
P x 0.0668 m³ = 2.77 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
P = 102.7 kPa