Question

An alloy of tin is 14% tin and weighs 22 pounds. A second alloy is 9% tin. How much of the second alloy must be added to the first alloy to get a 12% mixture. 7.33 7.7 11 14.67

Answer 1

I believe the answer would be 14.67 someone let me know 

Answer 2

Answer: 14.67 pounds of second alloy must be added to the first alloy to get 12% mixture.

Explanation:

Since we have given that

A alloy of 14% tin weigh 22 pounds.

There is a second alloy of 9% tin .

we need to find the quantity of second alloy that must be added to first alloy get a 12% mixture.

We will use "Mixture Alligation":

Ist alloy IInd alloy

14% 9%

12%

-------------------------------------

12-9 : 14-12

3 : 2

Since Ist alloy = 22 pounds

According to question, it becomes,

`(3)/(2)=(22)/(x)\\\\2* 22=3x\\\\44=3x\\\\(44)/(3)=x\\\\14.67=x`

Hence, 14.67 pounds of second alloy must be added to the first alloy to get 12% mixture.