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Sinθ=1/4, 0<θ<90; cosθ
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Sinθ=1/4, 0<θ<90; cosθ
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Oct 12, 2019
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Sinθ=1/4, 0<θ<90; cosθ
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Try this option:
1. rule: if θ∈(0;90°), then cosθ>0 and sinθ>0;
2. using the rule and sin²θ+cos²θ=1, ⇒ cosθ=√(1-sin²θ)=√15/4.
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Zxcmehran
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Oct 17, 2019
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