Answer:
If an angle is inscribed in a semicircle, it will be half the measure of a semicircle (180°), that is, measuring 90 degrees.
According to the given diagram,
Q, S, L, T, R and W are the points of the circumference of the circle having center O,
Also, AB is the diameter of the given circle,
∠AQB, ∠ASB, ∠ALB, ∠ATB, ∠ARB and ∠AWB are the angles on the semicircle,
Thus, by the above property,
m∠AQB = 90°
m∠ASB = 90°
m∠ALB = 90°
m∠ATB = 90°
m∠ARB = 90°
m∠AWB = 90°
If m∠BWD = x
Since, By the diagram,
m∠BWD < m∠AWD
⇒ m∠BWD < 90°
⇒ x < 90°