A wrecking ball is basically a sphere. So, to solve this problem we are going to use the volume formula for a sphere:

where

is the radius of the sphere
We know for our problem that the diameter of the wrecking ball is 3.5 ft, so

. To find its radius, we'll use the formula

:


Now we can replace the radius in our formula to find the volume of our wrecking ball:



We can conclude that the volume of our wrecking ball is 22.45

.