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Given:

2C8H18 + 25O2 → 16CO2 + 18H2O

In the combustion of octane, how many grams of oxygen are needed to completely react and produce 84.00 grams of carbon dioxide? Use the periodic table to get the weights of the elements.

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2 Answers

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Given: 2C8H18 + 25O2 → 16CO2 + 18H2O In the combustion of octane, how many grams of-example-1
User Blaine
by
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6 votes

Answer:

84.00g CO2 * 1mol CO2/44.009g CO2 * 25mol O2/16mol CO2 * 31.998g O2/1mol O2 = 95.43g O2

Step-by-step explanation:

User Vladimir Lagunov
by
3.5k points