Question

Please help me thank youuu

Answer 1

well, let's move like the crab, backwards, and start off with

3)

Check the picture below.

`tan(A )=\cfrac{\stackrel{opposite}{BC}}{\underset{adjacent}{AC}}\implies tan(A)=\cfrac{\stackrel{opposite}{3}}{\underset{adjacent}{4}}\qquad \textit{now let's find the \underline{hypotenuse}} \\\\[-0.35em] ~\dotfill`

`\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=√(a^2 + b^2) \qquad \begin{cases} c=\stackrel{hypotenuse}{AC}\\ a=\stackrel{adjacent}{4}\\ b=\stackrel{opposite}{3}\\ \end{cases} \\\\\\ AB=√((AC)^2 + (BC)^2)\implies AB=√(4^2 + 3^2)\implies \underline{AB=5} \\\\[-0.35em] ~\dotfill\\\\ sin(A )=\cfrac{\stackrel{opposite}{3}}{\underset{hypotenuse}{5}}\hspace{5em} cos(\theta )=\cfrac{\stackrel{adjacent}{4}}{\underset{hypotenuse}{5}}`

2)

well, Graciella said they couldn't just using the tangent they were given, well, she needs stop playing Angry Birds too much.

1)

well, from what I read, Angelica thought it was possible, so she was correct all along, I don't see any mistakes in her statements, all we did in 3) was what Angelica suggested.