Answer with explanation:
Length of the Model which is in the shape of rectangle= (x+2) meter
Breadth of the Model which is in the shape of rectangle = (2 x + 2) meter
Area of Rectangle = Breadth × Length
→(x+2)×(2 x +2)=130
→x×(2 x +2) +2×(2 x +2)=130
→2 x²+2 x +4 x +4=130→→Using Distributive property of Multiplication with respect to addition which is, a×(b+c)=a×b +a×c
→2 x²+ 6 x +4-130=0
→2 x²+ 6 x-126=0
→2×(x²+3 x -63)=0
→x²+3 x -63=0
→→Solution of Quadratic by completing the square
![\rightarrow (x+(3)/(2))^2-[(3)/(2)]^2-63=0\\\\ (x+(3)/(2))^2=63 +(9)/(4)\\\\(x+(3)/(2))^2=(261)/(4)\\\\(x+(3)/(2))=\pm \sqrt{(261)/(4)}\\\\(x+(3)/(2))=\pm(16.16)/(2)\\\\x+1.50=8.08\\\\\text{as sides of rectangle can't be negative}}\\\\x=8.08 -1.50\\\\x=6.58](https://img.qammunity.org/2019/formulas/mathematics/high-school/30lbmwgyqjn24yt3obd7pbd9gy7nbo3uhk.png)
Option C:→ (x + 2)(2 x + 2) = 130; x = 6.58 m