Question

1. Find the distance between two

points with coordinates (-2.6, -4.7)
and (-2.6, 4.7).
A) 2.6 units
B) 5.2 units
C) 7.3 units
D) 9.4 units
PLSS help me I’m slow

Answer 1

`\mathrm{D)\:}9.4\: \mathrm{units}`

Explanation:

Solution 1:

Notice the
`x` coordinate of both points are equal, meaning both points are on a vertical line. The distance between two points on a vertical line is the absolute difference of their y-coordinates. The absolute difference between
`4.7` and
`-4.7` is
`|4.7-4.7|=\fbox{$9.4$}`.

Solution 2:

The distance between two points
`(x_1,y_1)` and
`(x_2,y_2)` is:

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

Plugging in given values, we have:

`d=√((-2.6-(-2.6))^2+(4.7-(-4.7))^2),\\d=\fbox{$9.4$}`.