Question

If you started with 6g of cuso4 5h2o and 10 ml of 15m nh3, how many moles of each reagent were used

Answer 1

Moles of CUSO4.5H2O = masss/molar mass of CUSO4.5H2O ( 249.5 g/mol)

moles is therefore= 6g/ 249.5 g/mol = 0.024 moles


moles of NH3= molarity of NH3 x volume/1000

that is 10 x15/1000=0.15 moles