1. The quadratic formula is applied to solve quadratic equations. This is:
y=(-b±√(b²-4ac))/2a
2. Therefore, you have:
−5y²+2y=−2
−5y²+2y+2=0
a=-5
b=2
c=2
3. When you substitute these values into the quadratic formula, you obtain:
y=-2±√(2²-4(-5)(2))/2(-5)
y=-2±√44/-10
4. Therefore, you have:
y1=-0.46
y2=0.86