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A candy box is made from a piece of cardboard that measures 11 by 7 inches. squares of equal size will be cut out of each corner. the sides will then be folded up to form a rectangular box. what size square should be cut from each corner to obtain maximum​ volume?

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OK, here's what I've got:

Let x=one side of the square to be cut out of the corner
length of box=12-2x
width of box=8-2x
height of box=x

Volume=lwh
V(x)=(8-2x)(12-2x)(x)
=(96-16x-24x+4x^2)x
=(96-40x+4x^2)(x)
=96x-40x^2+4x^3

V'(x)=96-80x+12x^2

Set V'(x) to 0 to get the max volume, and use the quadratic formula to solve, but I'm not getting the right value for "x" according to the answer key. Have I set the problem up incorrectly? Thanks so much.
User Benny Tjia
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