Question

How can I factor this equation?


`9x^5 + 18x^4 - 82 {x}^(3) - 120 {x}^(2) + 185x + 150`
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Answer 1

factors are : (3x+2)(3x-5)(x²-5)(x+3)

Explanation:

given :
`9x^(5) +18x^(4) -82x^(3) -120x^(2)+185x+150`

( x + 3 ) is a factor of the following, can be found if " -3 " is replaced with x and put into equation and output is 0.

`9(-3)^(5) +18(-3)^(4) -82(-3)^(3) -120(-3)^(2)+185(-3)+150` = 0

as a result proved, ( x + 3 ) is a factor.

then divide, the following using ( x + 3 )

the answer should come = (3x+2)(3x-5)(x²-5)

so the factors are : (3x+2)(3x-5)(x²-5)(x+3)