Answer:
D) Object B is faster by a factor of 1.44
Explanation:
Using the table for Object A, we will find the equation representing its motion.
Since, slope =

So, substituting the slope and (2,5) in the equation 'y=mx+b', where m= slope, we get,
i.e. b = 0
So, the equation for the motion of Object A is,

Also, the equation for the motion of Object B is,

That is,
Speed of Object A =

Speed of Object B =

So, the factor of increase in the speed =
= 1.44
Hence, Object B is faster by a factor of 1.44.
Thus, option D is correct.