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X y

2 5
4 10
6 15
8 20


Object A and Object B are two objects in motion. Given the table of Object A and the equation y =
18
5
x of Object B, which of the two moving objects has greater speed and by what factor? (round to nearest hundredth)
A) Object A by a factor of 1.10
B) Object B by a factor of 1.10
C) Object A by a factor of 1.44
D) Object B by a factor of 1.44

User Carey
by
5.1k points

2 Answers

3 votes
The Answer is D:Object B by a factor of 1.44

Object A: 5/2 = 2.5
Object B: 18/5 = 3.6

That being so
3.6/2.5 = 1.44

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User NitroxDM
by
5.5k points
3 votes

Answer:

D) Object B is faster by a factor of 1.44

Explanation:

Using the table for Object A, we will find the equation representing its motion.

Since, slope =
(10-5)/(4-2)=(5)/(2)

So, substituting the slope and (2,5) in the equation 'y=mx+b', where m= slope, we get,


5=(5)/(2)* 2+b i.e. b = 0

So, the equation for the motion of Object A is,
y=(5)/(2)x

Also, the equation for the motion of Object B is,
y=(18)/(5)x

That is,

Speed of Object A =
(5)/(2)=2.5

Speed of Object B =
(18)/(5)=3.6

So, the factor of increase in the speed =
(3.6)/(2.5) = 1.44

Hence, Object B is faster by a factor of 1.44.

Thus, option D is correct.

User ExcellentSP
by
5.3k points