Question

Find the volume, in Liters, of 2.5 x 1024 molecules of chlorine gas at STP.

Answer 1

V = 93.0 L

Step-by-step explanation:

Hello!

In this case, when computing the PVT properties for an ideal gas, we need to use the following equation:

`PV=nRT`

In such a way, for 2.5 x 10²⁴ molecules of chlorine at STP (273.15 K and 1.00 atm) we first need the moles based on the Avogadro's number:

`n = 2.5x10^(24)molec*(1mol)/(6.022x10^(23)molec) = 4.15mol`

Now, we solve for volume on the ideal gas equation to obtain:

`V=(nRT)/(P)`

So we plug in and get:

`V=(4.15mol**0.08206(atm*L)/(mol*K)*273.15K)/(1.00atm)\\\\V=93.0L`

Best regards!