What is the value of x in simplest radical form ?

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asked Apr 3, 2019 132k views

1 Answer

Denis Kuzin · Answer 1 · 2019-04-09T19:53:03+0000

Solve for X (hypotenuse)

Hypotenuse =
$\sqrt{a^(2)+b^(2)}$

Substitute 20 for A and 21 for B

$\sqrt{20^(2)+21^(2)}$

Solve exponents
20^2 = 400
21^2 = 441
Hypotenuse =
√(400 + 441)

Add
400 + 441 = 841
Hypotenuse =
√(841)

Solve square root

√(841)

= 29
Hypotenuse = 29

What is the value of x in simplest radical form ?

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