Question

i haven't submitted a single assignment for this class since winter break bc i didn't realize she was assigning things on goformative and not schoology and now we're on trigonometric ratios i'm confused help me ​

Answer 1

Answer and Step-by-step explanation:

Trigonometric Function (These only work for right triangles):

SOH-CAH-TOA

S = Sine = sin

C = Cosine = cos

T = Tangent = tan

O = Opposite (side)

H = Hypotenuse (side)

A = Adjacent (side)

SOH = sin(angle) =
`(opposite)/(hypotenuse)`

CAH = cos(angle) =
`(adjacent)/(hypotenuse)`

TOA = tan(angle) =
`(opposite)/(adjacent)`

1. sinQ (Q is the angle) =
`(14)/(50) = (7)/(25) = 0.28`

Use Pythagorean Theorem to find side PQ.
`14^(2) + PQ^(2)= 50^(2) \\PQ^(2) = 2304\\PQ = 48`

2. cosQ =
`(48)/(50) = (24)/(25) = 0.96`

3. tanQ =
`(14)/(48) = (7)/(24) = 0.29`