The answer is 1 3 3 1
The coefficients of the expanded terms are a combination; 4C1 , 4C2, 4C3, 4C4 multiplied by the x, y coefficients in the parenthesis. Since x, y coefficients in parenthesis is 1 the expanded coefficients are just the combinations.
4C1 = 1
4C2 = 3
4C3 = 3
4C4 = 1
