Question

Where does the graph of y = sin x from x = 0 to x = 2π start?

A. At its minimum

B. At an x-intercept

C. At its maximum

D. Between an x-intercept and its maximum

Answer 1

the graph starts at an x intercept.

Answer 2

The graph of y=sin x start from x-intercept.

B is correct.

Explanation:

Given:
`y=\sin x`

From
`x=0\text{ to }x=2\pi`

We need to find starting point of graph.

Graph will start when x=0

Put x = 0 into y = sin x

We get,

y = sin (0)

y = 0

Starting point is (0,0)

The value of y is 0.

It would be x-intercept of graph.

Hence, The graph of y=sin x start from x-intercept.