Question

What is the average acceleration of the particle between 0 seconds and 4 seconds with a velocity of 2m/s

Answer 1

The average acceleration of the particle between 0 seconds and 4 seconds with a velocity of 2m/s is 0.5 m/s².

Step-by-step explanation:

The average acceleration of an object can be calculated by dividing the change in velocity by the time interval. In this case, the velocity of the particle changes from 0 m/s to 2 m/s over a time interval of 4 seconds. Therefore, the change in velocity is 2 m/s - 0 m/s = 2 m/s. The average acceleration is then calculated as (change in velocity) / (time interval) = 2 m/s / 4 s = 0.5 m/s².

Answer 2

Step-by-step explanation:

Average acceleration is defined as change in velocity divided by change in time.

Mathematically, a =
`(\Delta v)/(\Delta t)`

Since, it is given that change in velocity is 2 m/s. On the other hand,
`t_(1)` = 0 sec and
`t_(2)` = 4 sec.

Therefore, calculate average acceleration as follows.

a =
`(\Delta v)/(\Delta t)`

=
`(\Delta v)/(t_(2) - t_(1))`

=
`(2 m/s)/(4 sec - 0 sec)`

= 0.5
`m/s^(2)`

Therefore, we can conclude that average acceleration of the given particle is 0.5
`m/s^(2)`.