Question

is it right? but there isn't a square root for 3. And also I need an answer for the other one.. I need a great explanation quickly help!​

Answer 1

`x=0, \quad x=3`

Explanation:

Given equation:

`9x^2-27x=0`

Factor out the common term 9x:

`\implies 9x(x-3)=0`

Zero Product Property: If a⋅b = 0 then either a = 0 or b = 0 (or both).

Using the Zero Product Property, set each factor equal to zero and solve for x:

`\begin{aligned}\underline{\sf Case\; 1} & & \underline{\sf Case \;2}\\9x&=0 & x-3&=0\\(9x)/(9) & =(0)/(9) & \quad \quad x-3+3 & =0+3\\x&=0 & x&=3\end{aligned}`

Therefore, the solutions to the given equation are:

`x=0, \quad x=3`