Question

Plz help with this problem I need to find the length of CB???

Answer 1

`tan(30)=0.57735026919 \\ 0.57735026919= (x)/(20)`
Multiply by 20 on both sides

`0.57735026919*20= (x)/(20) *20 \\ 11.5470053838=x \\ 11.5=x`
and x = side CA
Next you now know the hypotenuse of the other "triangle"
It's Adjacent and hypotenuse
So that's cos

`cos(60)= (x)/(11.5) \\ 0.5= (x)/(11.5)`
multiply by 11.5 on both sides

`0.5*11.5= (x)/(11.5) * 11.5 \\ 5.75 = x`
x= side CB
CB=5.75m

Answer 2

CB is equal to 10m  you can tell this bye the side DC being 20 m and the angle of DC is half of CB so that means that CB has to be 10 m