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Convert 6.50g ZnSO4 to moles.

2 Answers

5 votes

Final answer:

To convert 6.50g of ZnSO4 to moles, divide the mass by the molar mass of ZnSO4, which is 161.4 g/mol. The result is 0.0403 mol.

Step-by-step explanation:

To convert from grams of ZnSO4 to moles, we need to use the molar mass of ZnSO4. The molar mass of ZnSO4 is the sum of the molar masses of zinc (Zn), sulfur (S), and oxygen (O). The molar mass of zinc (Zn) is 65.4 g/mol, the molar mass of sulfur (S) is 32 g/mol, and the molar mass of oxygen (O) is 16 g/mol.

Therefore, the molar mass of ZnSO4 is 65.4 g/mol + 32 g/mol + 16 g/mol = 161.4 g/mol.

To convert from grams to moles, we use the formula:

Moles = Mass / Molar Mass

So, to convert 6.50g ZnSO4 to moles:

Moles = 6.50g / 161.4 g/mol = 0.0403 mol

User Andrei Avram
by
6.3k points
4 votes


6,50g of ZnSO4 is 0,04 moles


Mass of ZnSO4 :

m=6,50g

Molar mass of ZnSO4 :

M=M(Zn)+M(S)+4*M(O)

M=65,38 g/mol+32,06 g/mol+4*15,99 g/mol

M=161,40 g/mol

Molarity of ZnSO4 :

n=m/M

n=6,50g/161,40g/mol

n=0,04 mol


User Mateo Randwolf
by
6.8k points