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(-3x^2y)^(4)


PLEASE EXPLAIN HOW YOU GOT YOUR ANSWER

User Ira Re
by
4.0k points

2 Answers

11 votes
When you have an power outside of a bracket, you have to multiply all the powers inside by the one outside...

So you would get x^2 x ^4 which is x^8

And y x ^4 which would be y^4

Therefore the answer will be -3x^8y^4

Hope this helps! Any questions let me know :)
User Anders Hansson
by
4.4k points
7 votes

Answer:

errr polynomials ahaha

so basically we can multiply the power outside of the parantheses with the exponents on the inside:

so


-3x^(2*4) y^(1*4)

this will give us:

-3x^8y^4

we also unfortunately, have to use the power on the coefficient -3 as well and we cant just MULTIPLY -3 by 4, we are going to have to multiply -3 with -3 4 TIMES(anytime we see a coefficient we MUST multiply the coefficient by itself according to the number outside of the parantheses)

so:

-3*-3*-3*-3=81

final expression


81x^(8)y^(4)

User Adewole Kayode
by
3.8k points