The standard equation of a circle is given by :

where (h,k) is the center and r is the radius of circle.
Now in the question we are given that the center is at origin.
So coordinate of center becomes (h,k) =(0,0)
radius is r.
So plugging these values in the standard equation, we get,

Simplifying,

Answer is option first:
x² + y² =r²