Question

On a coordinate plane, a point is at (negative 4, negative 4) and (negative 4, negative 10).

What is the distance between (–4, –10) and (–4, –4)?
3 units
4 units
6 units
8 units

Answer 1

Option: C (6)

Explanation:

Answer 2

Option C.

Explanation:

Hey there!

The points are; (-4,-4) and (-4,-10).

Use distance formula.

`d = \sqrt{ {(x2 - x1)}^(2) + {(y2 - y1)}^(2) }`

~ Put all values.

`d = \sqrt{ {( - 4 + 4)}^(2) + ( { - 10 + 4)}^(2) }`

~ Simplify it.

`d = \sqrt{ {0}^(2) + ( { - 6)}^(2) }`

`d = √(36)`

Therefore, distance between the points is 6 units.

Hope it helps...