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Find the quadratic function whose graph has a vertex at (3, 5) and passes through the point (1, -3). Express the function in both standard and general forms

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Given vertex
(h,k) the equation of the parabola is:

f(x)=a(x-h)^2+k.
Our vertex is the point
(3,5) so the equation is:

f(x)=a(x-3)^2+5. It remains to find a. We will use the point (1,-3) like
this:
Substitute x=1 and f(1)=-3 in the equation above we get the equation:

-3=a(1-3)+5\\-3=-2a+5\\-2a=-8\\a=4
Equation of the parabola then:
f(x)=4(x-3)^2+5.
Expand in order to get the general form:

f(x)=4(x^2-3x+9)+5\\y=4x^2-12x+41

User AaronShockley
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