check the picture below.
so, is really just a circle with a diameter of 8, inscribed in a square whose sides are 8 each.
since the diameter of the circle is 8, its radius is half that, or r = 4.
now, if we get the area of the square, namely 8*8, that includes the circle's area, but if we also get the area of the circle, namely A =πr² and thus π4² and "subtract" it, we're in effect making a hole in the square, and what's leftover is the shaded region.
