Answer:
19.4 miles
Explanation:
Let x represent distance between the airplane and the airport in miles.
We have been given that an airplane is at an elevation of 35,000 ft when it starts its descent at a 20 degree angle of depression. We are asked to find the distance between the airplane and the airport in miles.
We can see that airplane, airport and angle of depression forms a right triangle with respect to ground. The side of 35,000 ft is opposite side and x is hypotenuse to 20 degree angle.





To convert our distance into miles, we will divide 102333.154 by 5280.



Therefore, the air distance between the airplane and the airport is 19.4 miles.