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Write a balanced equation showing how this nucleus decays to form an α particle: thorium−230.

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when an atomic nucleus emits an alpha particle it decay into an atom with atomic number 2 less and mass number 4 less. Thus Thorium 230 decay as follows.

230 90Th -------> 226 88Th + 4 2 He

thorium is in the atomic number 90 thus it during alpha decay it reduces to atomic number 88 while its 230 mass number reduces to 226
User Giovanni B
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