Question

Solve using the quadratic formula

Answer 1

w =
`3√(2)` or w =
`-3√(2)`

Explanation:

5w^2 - 90 = 0

5w^2 + 0w - 90 = 0

aw^2 + bw + c = 0 ----> a = 5, b = 0, c = -90

`w = \frac{-b +- \sqrt{b^(2) - 4ac} }{2a}`

`w = \frac{-0 +- \sqrt{0^(2) - 4(5)(-90)} }{2(5)}`

`w = \frac{-0 +- √(0 + 1800)} {10}`

`w = (0 +- √(1800))/(10)`

`w = (0 + √(1800) )/(10)` or
`w = (0 - √(1800))/(10)`

`w = (30√(2) )/(10)` or
`w = \frac{-30√(2)} {10}`

`w = 3√(2)` or
`w = - 3√(2)`

Hope this helps!