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Please help me understand this

Please help me understand this-example-1
User Ekim
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2 Answers

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QS bisects <PQT so <PQS = <SQT
m<SQT = 8x - 25
m<PQT = 9x + 34
m<PQT = 2(m<SQT)
9x + 34 = 2(8x - 25)
9x + 34 = 16x - 50
7x = 84
x = 12

m<SQT = 8(12) - 25 = 71

m<PQS = m<SQT = 71

m<PQT = 2(m<PQS) = 2(71) = 142

m<TQR = m<SQR - m<SQT = 112 - 71 = 41

answer
x = 12
m<PQS = 71
m<PQT = 142
m<TQR = 41
User Troskyvs
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9.3k points
3 votes

Answer:

The value of x is 12.

The measure of ∠PQS is 71°.

The measure of ∠PQT is 142°.

The measure of ∠TQR is 41°.

Explanation:

Given information: QS bisects ∠PQT, m∠SQT=(8x-25)°, m∠PQT=(9x+34)° and m∠SQR=112°.

QS bisects ∠PQT it means QS divides ∠PQT in two equal parts.


\angle PQS=\angle SQT .... (1)


\angle SQT=(1)/(2)(\angle PQT)


2\angle SQT=\angle PQT

Substitute the value of each angle.


2(8x-25)=(9x+34)


16x-50=9x+34

Isolate variable terms.


16x-9x=50+34


7x=84

Divide both sides by 7.


x=12

The value of x is 12.

From equation (1) we get


\angle PQS=\angle SQT=(8x-25)^(\circ)


\angle PQS=(8(12)-25)^(\circ)


\angle PQS=71^(\circ)

The measure of ∠PQS is 71°.


m∠PQT=(9x+34)^(\circ)


m∠PQT=(9(12)+34)^(\circ)


m∠PQT=142^(\circ)

The measure of ∠PQT is 142°.


m∠TQR=m\angle SQR-m\angle SQT


m∠TQR=112^(\circ)-71^(\circ)


m∠TQR=41^(\circ)

The measure of ∠TQR is 41°.

User Stefangachter
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