Answer: 19 Quarters
Explanation:
We have two variables, d and q, representing the number of dimes and quarters that Andrew has, respectively.
From the problem, we have two equations:
$0.1d + $0.25q = $8.85 (the total amount of money in dimes and quarters is $8.85)
d = 2q + 3 (the number of dimes is 3 more than twice the number of quarters)
We can substitute equation (2) into equation (1) to eliminate d:
$0.1(2q+3) + $0.25q = $8.85
Simplifying the left-hand side, we get:
$0.2q + $0.3 + $0.25q = $8.85
Combining like terms, we get:
$0.45q + $0.3 = $8.85
Subtracting $0.3 from both sides, we get:
$0.45q = $8.55
Dividing both sides by $0.45, we get:
q = 19
Therefore, Andrew has 19 quarters.
To check this answer, we can substitute q = 19 into equation (2) to find the number of dimes:
d = 2(19) + 3 = 41
Then, we can check that the total amount of money is indeed $8.85:
$0.1(41) + $0.25(19) = $4.10 + $4.75 = $8.85
So the solution is q = 19, and Andrew has 19 quarters.