229k views
5 votes
What are the intercepts of

2x + 3y - 6z = 30?
A: (15, 0, 0), (0, 10, 0), (0, 0, 5)
B: (15, 0, 0), (0, -10, 0), (0, 0, 5)
C: (15, 0, 0), (0, -10, 0), (0, 0, -5)
D: (15, 0, 0), (0, 10, 0), (0, 0, -5)

User Lucas Paz
by
6.9k points

2 Answers

7 votes
my answer is D
first: type this code
then : press Calc ...

What are the intercepts of 2x + 3y - 6z = 30? A: (15, 0, 0), (0, 10, 0), (0, 0, 5) B-example-1
User Moataz Elmasry
by
6.7k points
2 votes

Answer:

Option (d) is correct.

Intercept of equation 2x + 3y - 6z = 30 is (15,0,0) ,(0,10,0) and (0,0,-5)

Explanation:

given : The equation 2x + 3y - 6z = 30

We have to find the intercept.

Intercept are the point where equations cut the x- axis, y- axis and z- axis.

Thus, at x- axis

y and z both are zero .

So, put y = z = 0

we get,

2x + 3(0) - 6(0) = 30

2x = 30

x = 15

at y- axis

x and z both are zero .

So, put x = z = 0

we get,

2(0) + 3y - 6(0) = 30

3y = 30

y = 10

at z- axis

y and x both are zero .

So, put y = x = 0

we get,

2(0)+ 3(0) - 6z = 30

-6z = 30

z= -5

Thus, intercept of equation 2x + 3y - 6z = 30 is (15,0,0) ,(0,10,0) and (0,0,-5)

User Juan Leni
by
6.7k points