Question

When 711 J of heat is added to a 41.1 g of an unknown metal, the temperature of the metal increases from 22oC to 94oC. Calculate the specific heat of this metal

Answer 1

the specific heat capacity of the metal is calculated as follows

heat energy = Mc delta T
heat energy (Q) = (711 j )
m=mass (41.1 g)
c= specific heat capacity =?
delta t = change in temperature( 94 -22=72)

c= Q/m delta T
c=711 j / (41.1 g x72) = 0.240 j/g /k