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2 votes
How many positive integers $n$ satisfy $\lfloor \sqrt{n} \rfloor = 5$?

User PepperBob
by
8.0k points

1 Answer

4 votes
For this case we have the following equation:
root (n) = 5
Clearing n we have:
n = 5 ^ 2
n = 25
Answer:
A positive integers n that satisfy root (n) = 5 is:
n = 25
(only one integer satisfies the equation given in the problem)
User Jpw
by
8.3k points
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