Question

A rectangle has dimensions 10 cm by 6 cm. determine the measures of the angles at the point of where the diagonals intersect

Answer 1

see the attached figure to better understand the problem

we know that

in the triangle ABC
tan(alfa/2)=AC/BC----> 5/3
so
(alfa/2)=arctan (5/3)---------> 59.0362°
alfa=2*59.0362--------> alfa=118.07°
alfa+beta=180°----------> because are supplementary angles
beta=180-118.07-------> beta=61.93°

the answer is
the angles are
alfa=118.07°
beta=61.93°